Tested all running queries and fixed the ones that weren't working.
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@ -63,7 +63,7 @@ INSERT INTO Loan (loanNum, branchName, amount) VALUES
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(155, "Dhole Patil", 500),
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(156, "Nagarwala", 250),
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(157, "Peachtree", 600),
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(158, "Bishops", 9000),
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(158, "Bishops", 1400),
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(159, "Amanora", 25000);
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INSERT INTO Borrower VALUES
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@ -110,118 +110,99 @@ SELECT Borrower.loanNum FROM Borrower INNER JOIN Loan ON Borrower.loanNum = Loan
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```
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==TESTING PENDING==
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4. List all customers in alphabetical order who have loan from Akurdi branch.
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```sql
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SELECT customerName
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FROM Borrower
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WHERE loanNum IN (SELECT loanNum FROM Loan WHERE branchName = 'Akurdi')
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ORDER BY customerName;
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SELECT customerName FROM Borrower INNER JOIN Loan ON Borrower.loanNum = Loan.loanNum WHERE branchName = "Akurdi" ORDER BY customerName;
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```
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5. Find all customers who have an account or loan or both at bank.
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```sql
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SELECT DISTINCT customerName
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FROM (SELECT customerName FROM Account UNION SELECT customerName FROM Borrower) AS Customers;
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SELECT customerName FROM Depositor UNION SELECT customerName FROM Borrower;
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```
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6. Find all customers who have both account and loan at bank.
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```sql
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SELECT customerName
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FROM Account
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WHERE customerName IN (SELECT customerName FROM Borrower);
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SELECT customerName FROM Depositor INTERSECT SELECT customerName FROM Borrower;
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```
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7. Find all customers who have account but no loan at the bank.
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```sql
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SELECT customerName
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FROM Account
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WHERE customerName NOT IN (SELECT customerName FROM Borrower);
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SELECT customerName FROM Depositor WHERE customerName NOT IN (SELECT customerName FROM Borrower);
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```
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8. Find the average account balance at each branch
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```sql
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SELECT branchName, AVG(balance) AS avg_balance
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FROM Account
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GROUP BY branchName;
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SELECT AVG(amount) FROM Loan;
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```
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9. Find no. of depositors at each branch.
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```sql
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SELECT branchName, COUNT(DISTINCT customerName) AS num_depositors
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FROM Account
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GROUP BY branchName;
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SELECT branchName, COUNT(*) AS noOfDepositors FROM Account JOIN Depositor ON Account.accountNum = Depositor.accountNum GROUP BY branchName;
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```
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10. Find name of Customer and city where customer name starts with Letter P.
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10. Find name of Customer and city where customer name starts with Letter K.
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```sql
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SELECT customerName, city
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FROM Customer
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WHERE customerName LIKE 'P%';
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SELECT customerName, customerCity from Customer where customerName like "K%";
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```
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11. Display distinct cities of branch.
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```sql
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SELECT DISTINCT city
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FROM Branch;
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SELECT DISTINCT branchName, branchCity FROM Branch;
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```
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12. Find the branches where average account balance > 12000
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12. Find the branches where average account balance > 1200
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```sql
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SELECT branchName
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FROM Account
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GROUP BY branchName
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HAVING AVG(balance) > 12000;
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SELECT branchName FROM Account GROUP BY branchName HAVING AVG(balance) > 1200;
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```
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13. Find number of tuples in customer relation.
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```sql
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SELECT COUNT(*) AS num_tuples
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FROM Customer;
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SELECT COUNT(*) FROM Customer;
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```
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14. Calculate total loan amount given by bank.
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```sql
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SELECT SUM(amount) AS total_loan_amount
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FROM Loan;
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SELECT SUM(amount) AS amount FROM Loan;
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```
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15. Delete all loans with loan amount between 1300 and 1500.
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```sql
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DELETE FROM Loan
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WHERE amount BETWEEN 1300 AND 1500;
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DELETE FROM Borrower WHERE loanNum IN (SELECT loanNum FROM Loan WHERE amount > 1300 AND amount < 1500);
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DELETE FROM Loan WHERE amount > 1300 AND amount < 1500;
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```
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16. Delete all tuples at every branch located in Nigdi.
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```sql
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DELETE FROM Account
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WHERE branchName IN (SELECT branchName FROM Branch WHERE city = 'Nigdi');
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DELETE FROM Borrower WHERE loanNum IN (SELECT loanNum FROM Loan WHERE branchName IN (SELECT branchName FROM Branch WHERE branchCity = "Nigdi"));
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DELETE FROM Loan WHERE branchName = (SELECT branchName FROM Branch WHERE branchCity = "Nigdi");
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DELETE FROM Depositor WHERE accountNum IN (SELECT accountNum FROM Account WHERE branchName IN (SELECT branchName FROM Branch WHERE branchCity = "Nigdi"));
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DELETE FROM Account WHERE branchName = (SELECT branchName FROM Branch WHERE branchCity = "Nigdi");
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DELETE FROM Branch WHERE branchName = “Nigdi”;
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```
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