Added content.

- Notes
- Practical (Databases, Handouts, Queries, Softcopies, Write-ups)
- Question Papers
- DISCLAIMER file and motto
Lastly, updated README file.

Practical/Assignment-B2/Queries-B2.md

@@ -0,0 +1,206 @@
+## Queries-B2
+
+### Group A
+
+> [!NOTE]
+> Use Employee database created in Assignment B-01 and perform following aggregation operation
+> Refer [Queries-B1](https://git.kska.io/sppu-te-comp-content/DatabaseManagementSystems/src/branch/main/Practical/Assignment-B1/Queries-B1.md)
+
+1. Return Designation with Total Salary Above 20000:
+```mongodb
+db.Employee.aggregate([
+    {
+        $group: {
+            _id: "$Designation",
+            TotalSalary: { $sum: "$Salary" }
+        }
+    },
+    {
+        $match: {
+            TotalSalary: { $gt: 20000 }
+        }
+    }
+])
+
+```
+
+2. Find Employee with Total Salary for Each City with Designation "Developer":
+```mongodb
+db.Employee.aggregate([
+  {
+    $match: {
+      Designation: "Developer"
+    }
+  },
+  {
+    $group: {
+      _id: "$Address.PAddr",
+      Total: { $sum: "$Salary" }
+    }
+  }
+])
+
+
+```
+
+3. Find Total Salary of Employee with Designation "Tester" for Each Company:
+```mongodb
+db.Employee.aggregate([
+    {
+        $match: { Designation: "Tester" }
+    },
+    {
+        $group: {
+            _id: "$Company_name",
+            TotalSalary: { $sum: "$Salary" }
+        }
+    }
+])
+
+```
+
+4. Returns Names and _id in Upper Case and in Alphabetical Order:
+```mongodb
+db.Employee.aggregate([
+    {
+        $project: {
+            _id: 1,
+            Name: { $toUpper: { $concat: ["$Name.FName", " ", "$Name.LName"] } }
+        }
+    },
+    {
+        $sort: { Name: 1 }
+    }
+])
+
+```
+
+5. Count All Records from Collection:
+```mongodb
+db.Employee.countDocuments()
+
+```
+
+6. For Each Unique Designation, Find Avg Salary and Output Sorted by AvgSal:
+```mongodb
+db.Employee.aggregate([
+    {
+        $group: {
+            _id: "$Designation",
+            AvgSalary: { $avg: "$Salary" }
+        }
+    },
+    {
+        $sort: { AvgSalary: 1 }
+    }
+])
+
+```
+
+7. Return Separate Value in the Expertise Array Where Name of Employee is "Aditya":
+```mongodb
+db.Employee.aggregate([
+    {
+        $match: { "Name.FName": "Aditya" }
+    },
+    {
+        $unwind: "$Expertise"
+    },
+    {
+        $project: { Expertise: 1 }
+    }
+])
+
+```
+
+8. Return Separate Value in the Expertise Array and Return Sum of Each Element of Array:
+```mongodb
+db.Employee.aggregate([
+    {
+        $unwind: "$Expertise"
+    },
+    {
+        $group: {
+            _id: "$Expertise",
+            TotalCount: { $sum: 1 }
+        }
+    }
+])
+
+```
+
+9. Return Array for Designation Whose Address is "Pune":
+```mongodb
+db.Employee.aggregate([
+    {
+        $match: { "Address.PAddr": { $regex: "Pune" } }
+    },
+    {
+        $project: { Designation: 1 }
+    }
+])
+
+```
+
+10. Return Max and Min Salary for Each Company:
+```mongodb
+db.Employee.aggregate([
+    {
+        $group: {
+            _id: "$Company_name",
+            MaxSalary: { $max: "$Salary" },
+            MinSalary: { $min: "$Salary" }
+        }
+    }
+])
+
+```
+
+### Group B
+
+> [!NOTE]
+> Use Employee database created in Assignment B-01 and perform following aggregation operation
+> Refer [Queries-B1](https://git.kska.io/sppu-te-comp-content/DatabaseManagementSystems/src/branch/main/Practical/Assignment-B1/Queries-B1.md)
+
+
+1. Create Single Field Indexes on Designation:
+```mongodb
+db.Employee.createIndex({ Designation: 1 })
+
+```
+
+2. Create Compound Indexes on Name and Age:
+```mongodb
+db.Employee.createIndex({ "Name.FName": 1, Age: -1 })
+
+```
+
+3. Create Multikey Indexes on Expertise Array:
+```mongodb
+db.Employee.createIndex({ Expertise: 1 })
+
+```
+
+4. Return a List of All Indexes on Collection:
+```mongodb
+db.Employee.getIndexes()
+
+```
+
+5. Rebuild Indexes:
+```mongodb
+db.Employee.reIndex()
+
+```
+
+6. Drop Index on Remove Specific Index:
+```mongodb
+db.Employee.dropIndex("Designation_1")
+
+```
+
+7. Remove All Indexes Except for the _id Index from a Collection:
+```mongodb
+db.Employee.dropIndexes()
+
+```