Added running queries, testing pending from 4-16.

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K 2024-07-25 14:31:34 +05:30
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@ -1,6 +1,6 @@
# Queries for Assignment-A2
# Database Queries for Assignment-A2
This file contains all the queries required to build the [database](https://git.kska.io/DatabaseManagementSystems/src/branch/main/Practical/Assignment-A2/Database_A2.sql)
This file contains all the queries required to build the [database](https://git.kska.io/sppu-te-comp-content/DatabaseManagementSystems/src/branch/main/Practical/Assignment-A2/Database_A2.sql)
## Creating database
@ -63,8 +63,8 @@ INSERT INTO Loan (loanNum, branchName, amount) VALUES
(155, "Dhole Patil", 500),
(156, "Nagarwala", 250),
(157, "Peachtree", 600),
(158, "Bishops", 900),
(159, "Amanora", 2500);
(158, "Bishops", 9000),
(159, "Amanora", 25000);
INSERT INTO Borrower VALUES
("Kalas", 156),
@ -88,4 +88,141 @@ INSERT INTO Depositor VALUES
## Running queries
==PENDING==
1. Find the names of all branches in loan relation.
```sql
SELECT branchName FROM Loan;
```
2. Find all loan numbers for loans made at Akurdi Branch with loan amount > 12000.
```sql
SELECT loanNum FROM Loan WHERE amount>12000;
```
3. Find all customers who have a loan from bank. Find their names,loan_no and loan amount.
```sql
SELECT * from Borrower;
SELECT Borrower.loanNum FROM Borrower INNER JOIN Loan ON Borrower.loanNum = Loan.loanNum;
```
==TESTING PENDING==
4. List all customers in alphabetical order who have loan from Akurdi branch.
```sql
SELECT customerName
FROM Borrower
WHERE loanNum IN (SELECT loanNum FROM Loan WHERE branchName = 'Akurdi')
ORDER BY customerName;
```
5. Find all customers who have an account or loan or both at bank.
```sql
SELECT DISTINCT customerName
FROM (SELECT customerName FROM Account UNION SELECT customerName FROM Borrower) AS Customers;
```
6. Find all customers who have both account and loan at bank.
```sql
SELECT customerName
FROM Account
WHERE customerName IN (SELECT customerName FROM Borrower);
```
7. Find all customers who have account but no loan at the bank.
```sql
SELECT customerName
FROM Account
WHERE customerName NOT IN (SELECT customerName FROM Borrower);
```
8. Find the average account balance at each branch
```sql
SELECT branchName, AVG(balance) AS avg_balance
FROM Account
GROUP BY branchName;
```
9. Find no. of depositors at each branch.
```sql
SELECT branchName, COUNT(DISTINCT customerName) AS num_depositors
FROM Account
GROUP BY branchName;
```
10. Find name of Customer and city where customer name starts with Letter P.
```sql
SELECT customerName, city
FROM Customer
WHERE customerName LIKE 'P%';
```
11. Display distinct cities of branch.
```sql
SELECT DISTINCT city
FROM Branch;
```
12. Find the branches where average account balance > 12000
```sql
SELECT branchName
FROM Account
GROUP BY branchName
HAVING AVG(balance) > 12000;
```
13. Find number of tuples in customer relation.
```sql
SELECT COUNT(*) AS num_tuples
FROM Customer;
```
14. Calculate total loan amount given by bank.
```sql
SELECT SUM(amount) AS total_loan_amount
FROM Loan;
```
15. Delete all loans with loan amount between 1300 and 1500.
```sql
DELETE FROM Loan
WHERE amount BETWEEN 1300 AND 1500;
```
16. Delete all tuples at every branch located in Nigdi.
```sql
DELETE FROM Account
WHERE branchName IN (SELECT branchName FROM Branch WHERE city = 'Nigdi');
```
---