Added running queries, testing pending from 4-16.

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K 2024-07-25 14:31:34 +05:30
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@ -1,6 +1,6 @@
# Queries for Assignment-A2 # Database Queries for Assignment-A2
This file contains all the queries required to build the [database](https://git.kska.io/DatabaseManagementSystems/src/branch/main/Practical/Assignment-A2/Database_A2.sql) This file contains all the queries required to build the [database](https://git.kska.io/sppu-te-comp-content/DatabaseManagementSystems/src/branch/main/Practical/Assignment-A2/Database_A2.sql)
## Creating database ## Creating database
@ -63,8 +63,8 @@ INSERT INTO Loan (loanNum, branchName, amount) VALUES
(155, "Dhole Patil", 500), (155, "Dhole Patil", 500),
(156, "Nagarwala", 250), (156, "Nagarwala", 250),
(157, "Peachtree", 600), (157, "Peachtree", 600),
(158, "Bishops", 900), (158, "Bishops", 9000),
(159, "Amanora", 2500); (159, "Amanora", 25000);
INSERT INTO Borrower VALUES INSERT INTO Borrower VALUES
("Kalas", 156), ("Kalas", 156),
@ -88,4 +88,141 @@ INSERT INTO Depositor VALUES
## Running queries ## Running queries
==PENDING== 1. Find the names of all branches in loan relation.
```sql
SELECT branchName FROM Loan;
```
2. Find all loan numbers for loans made at Akurdi Branch with loan amount > 12000.
```sql
SELECT loanNum FROM Loan WHERE amount>12000;
```
3. Find all customers who have a loan from bank. Find their names,loan_no and loan amount.
```sql
SELECT * from Borrower;
SELECT Borrower.loanNum FROM Borrower INNER JOIN Loan ON Borrower.loanNum = Loan.loanNum;
```
==TESTING PENDING==
4. List all customers in alphabetical order who have loan from Akurdi branch.
```sql
SELECT customerName
FROM Borrower
WHERE loanNum IN (SELECT loanNum FROM Loan WHERE branchName = 'Akurdi')
ORDER BY customerName;
```
5. Find all customers who have an account or loan or both at bank.
```sql
SELECT DISTINCT customerName
FROM (SELECT customerName FROM Account UNION SELECT customerName FROM Borrower) AS Customers;
```
6. Find all customers who have both account and loan at bank.
```sql
SELECT customerName
FROM Account
WHERE customerName IN (SELECT customerName FROM Borrower);
```
7. Find all customers who have account but no loan at the bank.
```sql
SELECT customerName
FROM Account
WHERE customerName NOT IN (SELECT customerName FROM Borrower);
```
8. Find the average account balance at each branch
```sql
SELECT branchName, AVG(balance) AS avg_balance
FROM Account
GROUP BY branchName;
```
9. Find no. of depositors at each branch.
```sql
SELECT branchName, COUNT(DISTINCT customerName) AS num_depositors
FROM Account
GROUP BY branchName;
```
10. Find name of Customer and city where customer name starts with Letter P.
```sql
SELECT customerName, city
FROM Customer
WHERE customerName LIKE 'P%';
```
11. Display distinct cities of branch.
```sql
SELECT DISTINCT city
FROM Branch;
```
12. Find the branches where average account balance > 12000
```sql
SELECT branchName
FROM Account
GROUP BY branchName
HAVING AVG(balance) > 12000;
```
13. Find number of tuples in customer relation.
```sql
SELECT COUNT(*) AS num_tuples
FROM Customer;
```
14. Calculate total loan amount given by bank.
```sql
SELECT SUM(amount) AS total_loan_amount
FROM Loan;
```
15. Delete all loans with loan amount between 1300 and 1500.
```sql
DELETE FROM Loan
WHERE amount BETWEEN 1300 AND 1500;
```
16. Delete all tuples at every branch located in Nigdi.
```sql
DELETE FROM Account
WHERE branchName IN (SELECT branchName FROM Branch WHERE city = 'Nigdi');
```
---