From ba84cdf1ccc479592fad0026ad582ec701ee1925 Mon Sep 17 00:00:00 2001
From: Kshitij <kshitijk@tuta.io>
Date: Sat, 9 Nov 2024 01:54:49 +0530
Subject: [PATCH] Added queries for S4 (MySQL).

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+# S4 - SQL Queries (in MySQL)
+
+**Problem Statement:**
+SQL Queries:
+Create following tables with suitable constraints (primary key,
+foreign key, not null etc).
+Insert record and solve the following queries:
+Create table Cust_Master(Cust_no, Cust_name, Cust_addr)
+Create table Order(Order_no, Cust_no, Order_date, Qty_Ordered)
+Create Product (Product_no, Product_name, Order_no)
+1. List names of customers having 'A' as second letter in their
+name.
+2. Display order from Customer no C1002, C1005, C1007 and C1008
+3. List Clients who stay in either 'Banglore or 'Manglore'
+4. Display name of customers& the product_name they have purchase
+5. Create view View1 consisting of Cust_name, Product_name.
+6. Disply product_name and quantity purchase by each customer
+7. Perform different joint operation.
+
+---
+
+## Creating the database
+```sql
+CREATE DATABASE Store;
+USE Store;
+
+```
+
+## Creating tables:
+
+```sql
+CREATE TABLE Cust_Master (
+  Cust_no VARCHAR(255) NOT NULL,
+  Cust_name VARCHAR(255),
+  Cust_addr VARCHAR(255),
+  PRIMARY KEY (cust_no)
+);
+
+CREATE TABLE Orders (
+  -- Cannot have 'Order' as table name since it is a keyword reserved for 'ORDER BY' cause
+  Order_no INT,
+  Cust_no VARCHAR(255),
+  Order_date DATE,
+  Qty_Ordered INT,
+  PRIMARY KEY (Order_no)
+);
+
+CREATE TABLE Product (
+  Product_no INT,
+  Product_name VARCHAR(255),
+  Order_no INT
+);
+
+```
+
+## Declaring foreign keys
+
+```sql
+ALTER TABLE Orders ADD FOREIGN KEY (Cust_no) REFERENCES Cust_Master (Cust_no);
+ALTER TABLE Product ADD FOREIGN KEY (Order_no) REFERENCES Orders (Order_no);
+
+```
+
+## Inserting data
+
+```sql
+INSERT INTO Cust_Master VALUES
+('C1001', 'Kalas', 'Pune'),
+('C1002', 'Macho', 'Banglore'),
+('C1003', 'Gundeti', 'Chennai'),
+('C1005', 'Salvi',  'Manglore'),
+('C1006', 'Kshitij', 'Assam'),
+('C1007', 'Himashu', 'Banglore'),
+('C1008', 'Mehul', 'Mumbai');
+
+INSERT INTO Orders VALUES
+(1, 'C1001', '2024-11-09', 10),
+(2, 'C1003', '2024-11-01', 5),
+(3, 'C1005', '2024-11-05', 45),
+(4, 'C1002', '2024-10-29', 3),
+(5, 'C1007', '2024-10-15', 2),
+(6, 'C1008', '2024-11-10', 7),
+(7, 'C1006', '2024-11-09', 1);
+
+INSERT INTO Product VALUES
+('101', 'Political Stamps', 1),
+('204', 'Fashion Accessory', 2),
+('438', 'Complan', 3),
+('327', 'ID Card Strap', 4),
+('243', 'Face and Hair Wash', 5),
+('373', 'Fat Reducer 6000', 6),
+('327', 'Personality', 7);
+
+```
+
+## Queries
+
+1. List names of customers having 'A' as second letter in their name.
+```sql
+SELECT Cust_name FROM Cust_Master WHERE Cust_name LIKE "_a%";
+
+```
+
+2. Display order from Customer no C1002, C1005, C1007 and C1008
+```sql
+SELECT * FROM Orders WHERE Cust_no IN ('C1002', 'C1005', 'C1007', 'C1008');
+
+```
+
+3. List Clients who stay in either 'Banglore or 'Manglore'
+```sql
+SELECT Cust_name FROM Cust_Master WHERE Cust_addr = 'Banglore' OR Cust_addr = 'Manglore';
+
+```
+
+4. Display name of customers & the product_name they have purchase
+```sql
+SELECT Cust_Master.Cust_name, Product.Product_name FROM Product INNER JOIN Orders ON Product.Order_no = Orders.Order_no INNER JOIN Cust_Master ON Orders.Cust_no = Cust_Master.Cust_no;
+
+```
+
+5. Create view View1 consisting of Cust_name, Product_name.
+```sql
+CREATE VIEW View1 AS SELECT Cust_Master.Cust_name, Product.Product_name FROM Product INNER JOIN Orders ON Product.Order_no = Orders.Order_no INNER JOIN Cust_Master ON Orders.Cust_no = Cust_Master.Cust_no;
+
+SELECT * FROM View1;
+
+```
+
+6. Disply product_name and quantity purchase by each customer
+```sql
+SELECT Cust_Master.Cust_name, Product.Product_name, Orders.Qty_Ordered FROM Product INNER JOIN Orders ON Product.Order_no = Orders.Order_no INNER JOIN Cust_Master ON Orders.Cust_no = Cust_Master.Cust_no;
+
+```
+
+7. Perform different joint operation.
+
+- INNER JOIN:
+
+```sql
+SELECT Cust_Master.Cust_name, Product.Product_name FROM Product INNER JOIN Orders ON Product.Order_no = Orders.Order_no INNER JOIN Cust_Master ON Orders.Cust_no = Cust_Master.Cust_no;
+
+```
+
+- OUTER LEFT JOIN:
+
+```sql
+SELECT Cust_Master.Cust_name, Orders.Order_no, Orders.Order_date FROM Cust_Master LEFT JOIN Orders ON Cust_Master.Cust_no = Orders.Cust_no;
+
+```
+
+- OUTER RIGHT JOIN:
+
+```sql
+SELECT Orders.Order_no, Orders.Order_date, Cust_Master.Cust_name FROM Orders RIGHT JOIN Cust_Master ON Orders.Cust_no = Cust_Master.Cust_no;
+
+```
+
+---