Practical/Practical Exam/SQL/S3 - SQL Queries.md

@@ -167,5 +167,3 @@ SELECT branch_name, AVG(balance) FROM Account GROUP BY branch_name;
 SELECT cust_name, cust_city FROM Customer WHERE cust_name LIKE "P%";
 
 ```
-
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Practical/Practical Exam/SQL/S4 - SQL Queries.md

@@ -1,159 +0,0 @@
-# S4 - SQL Queries (in MySQL)
-
-**Problem Statement:**
-SQL Queries:
-Create following tables with suitable constraints (primary key,
-foreign key, not null etc).
-Insert record and solve the following queries:
-Create table Cust_Master(Cust_no, Cust_name, Cust_addr)
-Create table Order(Order_no, Cust_no, Order_date, Qty_Ordered)
-Create Product (Product_no, Product_name, Order_no)
-1. List names of customers having 'A' as second letter in their
-name.
-2. Display order from Customer no C1002, C1005, C1007 and C1008
-3. List Clients who stay in either 'Banglore or 'Manglore'
-4. Display name of customers& the product_name they have purchase
-5. Create view View1 consisting of Cust_name, Product_name.
-6. Disply product_name and quantity purchase by each customer
-7. Perform different joint operation.
-
----
-
-## Creating the database
-```sql
-CREATE DATABASE Store;
-USE Store;
-
-```
-
-## Creating tables:
-
-```sql
-CREATE TABLE Cust_Master (
-  Cust_no VARCHAR(255) NOT NULL,
-  Cust_name VARCHAR(255),
-  Cust_addr VARCHAR(255),
-  PRIMARY KEY (cust_no)
-);
-
-CREATE TABLE Orders (
-  -- Cannot have 'Order' as table name since it is a keyword reserved for 'ORDER BY' cause
-  Order_no INT,
-  Cust_no VARCHAR(255),
-  Order_date DATE,
-  Qty_Ordered INT,
-  PRIMARY KEY (Order_no)
-);
-
-CREATE TABLE Product (
-  Product_no INT,
-  Product_name VARCHAR(255),
-  Order_no INT
-);
-
-```
-
-## Declaring foreign keys
-
-```sql
-ALTER TABLE Orders ADD FOREIGN KEY (Cust_no) REFERENCES Cust_Master (Cust_no);
-ALTER TABLE Product ADD FOREIGN KEY (Order_no) REFERENCES Orders (Order_no);
-
-```
-
-## Inserting data
-
-```sql
-INSERT INTO Cust_Master VALUES
-('C1001', 'Kalas', 'Pune'),
-('C1002', 'Macho', 'Banglore'),
-('C1003', 'Gundeti', 'Chennai'),
-('C1005', 'Salvi',  'Manglore'),
-('C1006', 'Kshitij', 'Assam'),
-('C1007', 'Himashu', 'Banglore'),
-('C1008', 'Mehul', 'Mumbai');
-
-INSERT INTO Orders VALUES
-(1, 'C1001', '2024-11-09', 10),
-(2, 'C1003', '2024-11-01', 5),
-(3, 'C1005', '2024-11-05', 45),
-(4, 'C1002', '2024-10-29', 3),
-(5, 'C1007', '2024-10-15', 2),
-(6, 'C1008', '2024-11-10', 7),
-(7, 'C1006', '2024-11-09', 1);
-
-INSERT INTO Product VALUES
-('101', 'Political Stamps', 1),
-('204', 'Fashion Accessory', 2),
-('438', 'Complan', 3),
-('327', 'ID Card Strap', 4),
-('243', 'Face and Hair Wash', 5),
-('373', 'Fat Reducer 6000', 6),
-('327', 'Personality', 7);
-
-```
-
-## Queries
-
-1. List names of customers having 'A' as second letter in their name.
-```sql
-SELECT Cust_name FROM Cust_Master WHERE Cust_name LIKE "_a%";
-
-```
-
-2. Display order from Customer no C1002, C1005, C1007 and C1008
-```sql
-SELECT * FROM Orders WHERE Cust_no IN ('C1002', 'C1005', 'C1007', 'C1008');
-
-```
-
-3. List Clients who stay in either 'Banglore or 'Manglore'
-```sql
-SELECT Cust_name FROM Cust_Master WHERE Cust_addr = 'Banglore' OR Cust_addr = 'Manglore';
-
-```
-
-4. Display name of customers & the product_name they have purchase
-```sql
-SELECT Cust_Master.Cust_name, Product.Product_name FROM Product INNER JOIN Orders ON Product.Order_no = Orders.Order_no INNER JOIN Cust_Master ON Orders.Cust_no = Cust_Master.Cust_no;
-
-```
-
-5. Create view View1 consisting of Cust_name, Product_name.
-```sql
-CREATE VIEW View1 AS SELECT Cust_Master.Cust_name, Product.Product_name FROM Product INNER JOIN Orders ON Product.Order_no = Orders.Order_no INNER JOIN Cust_Master ON Orders.Cust_no = Cust_Master.Cust_no;
-
-SELECT * FROM View1;
-
-```
-
-6. Disply product_name and quantity purchase by each customer
-```sql
-SELECT Cust_Master.Cust_name, Product.Product_name, Orders.Qty_Ordered FROM Product INNER JOIN Orders ON Product.Order_no = Orders.Order_no INNER JOIN Cust_Master ON Orders.Cust_no = Cust_Master.Cust_no;
-
-```
-
-7. Perform different joint operation.
-
-- INNER JOIN:
-
-```sql
-SELECT Cust_Master.Cust_name, Product.Product_name FROM Product INNER JOIN Orders ON Product.Order_no = Orders.Order_no INNER JOIN Cust_Master ON Orders.Cust_no = Cust_Master.Cust_no;
-
-```
-
-- OUTER LEFT JOIN:
-
-```sql
-SELECT Cust_Master.Cust_name, Orders.Order_no, Orders.Order_date FROM Cust_Master LEFT JOIN Orders ON Cust_Master.Cust_no = Orders.Cust_no;
-
-```
-
-- OUTER RIGHT JOIN:
-
-```sql
-SELECT Orders.Order_no, Orders.Order_date, Cust_Master.Cust_name FROM Orders RIGHT JOIN Cust_Master ON Orders.Cust_no = Cust_Master.Cust_no;
-
-```
-
----