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@ -167,5 +167,3 @@ SELECT branch_name, AVG(balance) FROM Account GROUP BY branch_name;
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SELECT cust_name, cust_city FROM Customer WHERE cust_name LIKE "P%";
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SELECT cust_name, cust_city FROM Customer WHERE cust_name LIKE "P%";
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```
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```
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---
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@ -1,159 +0,0 @@
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# S4 - SQL Queries (in MySQL)
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**Problem Statement:**
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SQL Queries:
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Create following tables with suitable constraints (primary key,
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foreign key, not null etc).
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Insert record and solve the following queries:
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Create table Cust_Master(Cust_no, Cust_name, Cust_addr)
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Create table Order(Order_no, Cust_no, Order_date, Qty_Ordered)
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Create Product (Product_no, Product_name, Order_no)
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1. List names of customers having 'A' as second letter in their
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name.
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2. Display order from Customer no C1002, C1005, C1007 and C1008
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3. List Clients who stay in either 'Banglore or 'Manglore'
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4. Display name of customers& the product_name they have purchase
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5. Create view View1 consisting of Cust_name, Product_name.
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6. Disply product_name and quantity purchase by each customer
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7. Perform different joint operation.
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---
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## Creating the database
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```sql
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CREATE DATABASE Store;
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USE Store;
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```
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## Creating tables:
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```sql
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CREATE TABLE Cust_Master (
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Cust_no VARCHAR(255) NOT NULL,
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Cust_name VARCHAR(255),
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Cust_addr VARCHAR(255),
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PRIMARY KEY (cust_no)
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);
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CREATE TABLE Orders (
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-- Cannot have 'Order' as table name since it is a keyword reserved for 'ORDER BY' cause
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Order_no INT,
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Cust_no VARCHAR(255),
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Order_date DATE,
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Qty_Ordered INT,
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PRIMARY KEY (Order_no)
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);
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CREATE TABLE Product (
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Product_no INT,
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Product_name VARCHAR(255),
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Order_no INT
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);
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```
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## Declaring foreign keys
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```sql
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ALTER TABLE Orders ADD FOREIGN KEY (Cust_no) REFERENCES Cust_Master (Cust_no);
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ALTER TABLE Product ADD FOREIGN KEY (Order_no) REFERENCES Orders (Order_no);
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```
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## Inserting data
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```sql
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INSERT INTO Cust_Master VALUES
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('C1001', 'Kalas', 'Pune'),
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('C1002', 'Macho', 'Banglore'),
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('C1003', 'Gundeti', 'Chennai'),
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('C1005', 'Salvi', 'Manglore'),
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('C1006', 'Kshitij', 'Assam'),
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('C1007', 'Himashu', 'Banglore'),
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('C1008', 'Mehul', 'Mumbai');
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INSERT INTO Orders VALUES
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(1, 'C1001', '2024-11-09', 10),
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(2, 'C1003', '2024-11-01', 5),
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(3, 'C1005', '2024-11-05', 45),
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(4, 'C1002', '2024-10-29', 3),
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(5, 'C1007', '2024-10-15', 2),
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(6, 'C1008', '2024-11-10', 7),
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(7, 'C1006', '2024-11-09', 1);
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INSERT INTO Product VALUES
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('101', 'Political Stamps', 1),
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('204', 'Fashion Accessory', 2),
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('438', 'Complan', 3),
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('327', 'ID Card Strap', 4),
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('243', 'Face and Hair Wash', 5),
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('373', 'Fat Reducer 6000', 6),
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('327', 'Personality', 7);
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```
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## Queries
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1. List names of customers having 'A' as second letter in their name.
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```sql
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SELECT Cust_name FROM Cust_Master WHERE Cust_name LIKE "_a%";
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```
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2. Display order from Customer no C1002, C1005, C1007 and C1008
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```sql
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SELECT * FROM Orders WHERE Cust_no IN ('C1002', 'C1005', 'C1007', 'C1008');
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```
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3. List Clients who stay in either 'Banglore or 'Manglore'
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```sql
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SELECT Cust_name FROM Cust_Master WHERE Cust_addr = 'Banglore' OR Cust_addr = 'Manglore';
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```
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4. Display name of customers & the product_name they have purchase
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```sql
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SELECT Cust_Master.Cust_name, Product.Product_name FROM Product INNER JOIN Orders ON Product.Order_no = Orders.Order_no INNER JOIN Cust_Master ON Orders.Cust_no = Cust_Master.Cust_no;
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```
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5. Create view View1 consisting of Cust_name, Product_name.
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```sql
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CREATE VIEW View1 AS SELECT Cust_Master.Cust_name, Product.Product_name FROM Product INNER JOIN Orders ON Product.Order_no = Orders.Order_no INNER JOIN Cust_Master ON Orders.Cust_no = Cust_Master.Cust_no;
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SELECT * FROM View1;
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```
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6. Disply product_name and quantity purchase by each customer
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```sql
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SELECT Cust_Master.Cust_name, Product.Product_name, Orders.Qty_Ordered FROM Product INNER JOIN Orders ON Product.Order_no = Orders.Order_no INNER JOIN Cust_Master ON Orders.Cust_no = Cust_Master.Cust_no;
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```
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7. Perform different joint operation.
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- INNER JOIN:
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```sql
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SELECT Cust_Master.Cust_name, Product.Product_name FROM Product INNER JOIN Orders ON Product.Order_no = Orders.Order_no INNER JOIN Cust_Master ON Orders.Cust_no = Cust_Master.Cust_no;
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```
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- OUTER LEFT JOIN:
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```sql
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SELECT Cust_Master.Cust_name, Orders.Order_no, Orders.Order_date FROM Cust_Master LEFT JOIN Orders ON Cust_Master.Cust_no = Orders.Cust_no;
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```
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- OUTER RIGHT JOIN:
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```sql
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SELECT Orders.Order_no, Orders.Order_date, Cust_Master.Cust_name FROM Orders RIGHT JOIN Cust_Master ON Orders.Cust_no = Cust_Master.Cust_no;
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```
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---
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