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@ -4,6 +4,9 @@ This folder contains all the problem statements expected for practical examinati
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---
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##### [All problem statements](https://git.kska.io/sppu-te-comp-content/DatabaseManagementSystems/src/branch/main/Practical/Practical%20Exam/DBMSL%20-%20Problem%20Statements%20for%20Practical%20Exam%20%28November%202024%29.pdf).
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- [SQL](https://git.kska.io/sppu-te-comp-content/DatabaseManagementSystems/src/branch/main/Practical/Practical%20Exam/SQL) // 9 problem statements
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- [PL-SQL](https://git.kska.io/sppu-te-comp-content/DatabaseManagementSystems/src/branch/main/Practical/Practical%20Exam/PL-SQL) // 10 problem statements
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- [MongoDB](https://git.kska.io/sppu-te-comp-content/DatabaseManagementSystems/src/branch/main/Practical/Practical%20Exam/MongoDB) // 6 problem statements
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Practical/Practical Exam/S9 - SQL Queries.md
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135
Practical/Practical Exam/S9 - SQL Queries.md
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# S9 - SQL Queries (in MySQL)
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**Problem Statement:**
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SQL Queries
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Create following tables with suitable constraints. Insert data and
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solve the following queries:
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CUSTOMERS(_CNo_, Cname, Ccity, CMobile)
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ITEMS(_INo_, Iname, Itype, Iprice, Icount)
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PURCHASE(_PNo_, Pdate, Pquantity, Cno, INo)
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1. List all stationary items with price between 400/- to 1000/-
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2. Change the mobile number of customer “Gopal”
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3. Display the item with maximum price
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4. Display all purchases sorted from the most recent to the oldest
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5. Count the number of customers in every city
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6. Display all purchased quantity of Customer Maya
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7. Create view which shows Iname, Price and Count of all stationary
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items in descending order of price.
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---
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## Creating the database
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```sql
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CREATE DATABASE Store3;
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USE Store3;
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```
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## Creating tables:
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```sql
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CREATE TABLE Customers (
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CNo INT,
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Cname VARCHAR(255),
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Ccity VARCHAR(255),
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Cmobile BIGINT,
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PRIMARY KEY (CNo)
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);
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CREATE TABLE Items (
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INo INT,
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Iname VARCHAR(255),
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Itype VARCHAR(255),
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Iprice INT,
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Icount INT,
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PRIMARY KEY (Icount)
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);
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CREATE TABLE Purchase (
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PNo INT,
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Pdate DATE,
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Pquantity INT,
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Cno INT,
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INo INT,
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PRIMARY KEY (PNo),
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FOREIGN KEY (Cno) REFERENCES Customers (CNo)
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);
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```
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> [!WARNING]
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> Notice inconsistent naming for columns? We're just doing it by the books. Blame the one who made these [problem statements](https://git.kska.io/sppu-te-comp-content/DatabaseManagementSystems/src/branch/main/Practical/Practical%20Exam/DBMSL%20-%20Problem%20Statements%20for%20Practical%20Exam%20%28November%202024%29.pdf).
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## Inserting data
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```sql
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INSERT INTO Customers VALUES
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(1, 'Kalas', 'Pune', 9857265240),
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(2, 'Himanshu', 'Chennai', 9857265241),
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(3, 'Gopal', 'Mumbai', 9857265245),
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(4, 'Maya', 'Mumbai', 9857265243),
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(5, 'Mehul', 'Pune', 9857265244);
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INSERT INTO Items VALUES
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(101, 'Stamp', 'Collectables', 850, 10),
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(102, 'Pen', 'Instruments', 549, 50),
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(103, 'Sticky notes', 'Writing', 150, 200),
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(104, 'Geometry box', 'Instruments', 1350, 70),
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(105, 'Pencil', 'Instruments', 670, 45);
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INSERT INTO Purchase VALUES
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(201, '2024-11-05', 4, 1, 101),
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(202, '2024-11-07', 3, 2, 102),
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(203, '2024-11-08', 20, 3, 103),
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(204, '2024-10-29', 1, 4, 104),
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(205, '2024-11-10', 7, 5, 105);
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```
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## Queries
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1. List all stationary items with price between 400/- to 1000/-
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```sql
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SELECT Iname FROM Items WHERE Iprice BETWEEN 400 AND 1000;
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```
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2. Change the mobile number of customer “Gopal”
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```sql
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UPDATE Customers SET CMobile = 9857265242 WHERE Cname = "Gopal";
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SELECT * FROM Customers WHERE Cname = "Gopal";
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```
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3. Display the item with maximum price
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```sql
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SELECT Iname FROM Items WHERE Iprice = (SELECT MAX(Iprice) FROM Items);
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```
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4. Display all purchases sorted from the most recent to the oldest
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```sql
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SELECT * FROM Purchase ORDER BY Pdate DESC;
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```
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5. Count the number of customers in every city
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```sql
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SELECT COUNT(*), Ccity FROM Customers GROUP BY Ccity;
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```
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6. Display all purchased quantity of Customer Maya
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```sql
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SELECT Iname, Pquantity FROM Purchase INNER JOIN Customers ON Purchase.Cno = Customers.CNo INNER JOIN Items ON Purchase.INo = Items.INo WHERE Cname = "Maya";
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```
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7. Create view which shows Iname, Price and Count of all stationary items in descending order of price.
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```sql
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CREATE VIEW itemView AS SELECT Iname, Iprice, COUNT(*) FROM Items GROUP BY Iname, Iprice ORDER BY Iprice DESC;
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SELECT * FROM itemView;
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```
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---
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