271 lines
6.8 KiB
Markdown
Executable File
271 lines
6.8 KiB
Markdown
Executable File
## Creating database
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```sql
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CREATE DATABASE Database_A3;
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USE Database_A3;
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```
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## Creating tables and specify primary keys:
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```sql
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CREATE TABLE Account(acc_no INT, branch_name VARCHAR(50), balance INT, PRIMARY KEY (acc_no));
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CREATE TABLE Branch(branch_name VARCHAR(50), branch_city VARCHAR(50), assets INT, PRIMARY KEY (branch_name));
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CREATE TABLE Customer (cust_name VARCHAR(50), cust_street VARCHAR(50), cust_city VARCHAR(50), PRIMARY KEY (cust_name));
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CREATE TABLE Depositor (cust_name VARCHAR(50), acc_no INT);
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CREATE TABLE Loan (loan_no INT, branch_name VARCHAR(50), amount INT, PRIMARY KEY (loan_no));
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CREATE TABLE Borrower (cust_name VARCHAR(50), loan_no INT);
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```
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## Altering tables to specify foreign keys
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```sql
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ALTER TABLE Account ADD FOREIGN KEY (branch_name) REFERENCES Branch(branch_name);
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ALTER TABLE Depositor ADD FOREIGN KEY (cust_name) REFERENCES Customer (cust_name);
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ALTER TABLE Depositor ADD FOREIGN KEY (acc_no) REFERENCES Account (acc_no);
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ALTER TABLE Loan ADD FOREIGN KEY (branch_name) REFERENCES Branch (branch_name);
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ALTER TABLE Borrower ADD FOREIGN KEY (cust_name) REFERENCES Customer (cust_name);
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ALTER TABLE Borrower ADD FOREIGN KEY (loan_no) REFERENCES Loan (loan_no);
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```
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## Adding data
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```sql
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INSERT INTO Branch (branch_name, branch_city, assets) VALUES
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("Pune_Station", "Pune", 5000),
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("Hadapsar", "Pune", 20000),
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("Dhole_Patil", "Mumbai", 7500),
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("Nagarwala", "Nandurbar", 3200);
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INSERT INTO Customer (cust_name, cust_street, cust_city) VALUES
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("Kalas", "Airport Road", "Pune"),
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("Mehul", "Shahdha", "Nandurbar"),
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("Tanmay", "Porwal Road", "Pune"),
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("Kshitij", "Hadapasar", "Pune"),
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("Aditya", "Mira RD", "Mumbai"),
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("Himanshu", "Smart City", "Nandurbar");
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INSERT INTO Account (acc_no, branch_name, balance) VALUES
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(2501, "Dhole_Patil", 5000),
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(2511, "Pune_Station", 1500),
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(2521, "Hadapsar", 2000),
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(2512, "Nagarwala", 5000),
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(2531, "Pune_Station", 1000);
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INSERT INTO Loan (loan_no, branch_name, amount) VALUES
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(155, "Dhole_Patil", 500),
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(156, "Pune_Station", 250),
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(157, "Hadapsar", 600),
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(158, "Nagarwala", 1400),
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(159, "Pune_Station", 25000);
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INSERT INTO Borrower VALUES
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("Kalas", 156),
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("Mehul", 158),
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("Tanmay", 155),
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("Kshitij", 157),
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("Aditya", 159),
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("Himanshu", 158);
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INSERT INTO Depositor VALUES
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("Kalas", 2511),
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("Mehul", 2512),
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("Tanmay", 2501),
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("Kshitij", 2521),
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("Aditya", 2531),
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("Himanshu", 2512);
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```
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## Queries
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### Part 1 (Borrower):
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1. Create a View1 to display List all customers in alphabetical order who have loan from
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Pune_Station branch
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```sql
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CREATE VIEW View1 AS
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SELECT cust_name
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FROM Borrower
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INNER JOIN Loan ON Borrower.loan_no = Loan.loan_no
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WHERE branch_name = "Pune_Station"
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ORDER BY cust_name;
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SELECT * FROM View1;
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```
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2. Create View2 on branch table by selecting any two columns and perform insert
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update delete operations.
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```sql
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CREATE VIEW View2 AS
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SELECT branch_name, branch_city
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FROM Branch;
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SELECT * FROM View2;
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-- Insert operation
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INSERT INTO View2 (branch_name, branch_city) VALUES ('Yerwada', 'Pune');
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SELECT * FROM View2;
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-- Update operation
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UPDATE View2 SET branch_name = 'Peachtree' WHERE branch_name = 'Yerwada';
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SELECT * FROM View2;
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-- Delete operation
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DELETE FROM View2 WHERE branch_name = 'Peachtree';
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SELECT * FROM View2;
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```
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3. Create View3 on borrower and depositor table by selecting any one column from each
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table perform insert update delete operations.
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```sql
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CREATE VIEW View3 AS
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SELECT Borrower.cust_name, Depositor.acc_no
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FROM Borrower JOIN Depositor ON Borrower.cust_name = Depositor.cust_name;
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SELECT * FROM View3;
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-- Insert operation
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// NEED TO FIX THIS
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INSERT INTO Customer (cust_name, cust_street, cust_city) VALUES ("Sandy", "Pedgaon", "Ahemadnagar");
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INSERT INTO Borrower (cust_name, loan_no) VALUES ("Sandy", 160);
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INSERT INTO Depositor(cust_name, Acc_no) VALUES("Sandy", 2502);
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SELECT * FROM View3;
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-- Update operation
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UPDATE View3 SET acc_no = 102 WHERE cust_name = 'John_Doe';
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SELECT * FROM View3;
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-- Delete operation
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DELETE FROM View3 WHERE cust_name = 'John_Doe';
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SELECT * FROM View3;
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//
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```
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4. Create Union of left and right joint for all customers who have an account or loan or both at bank
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```sql
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SELECT DISTINCT Customer.cust_name
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FROM Customer
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LEFT JOIN Depositor ON Customer.cust_name = Depositor.cust_name
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LEFT JOIN Borrower ON Customer.cust_name = Borrower.cust_name
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WHERE Depositor.acc_no IS NOT NULL OR Borrower.loan_no IS NOT NULL;
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```
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5. Display content of View1, View2, View3
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```sql
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SELECT * FROM View1;
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SELECT * FROM View2;
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SELECT * FROM View3;
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```
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6. Create Simple and Unique index
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```sql
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-- Simple Index
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CREATE INDEX cust_ind ON Customer (cust_city);
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-- Unique Index
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CREATE UNIQUE INDEX branch_ind ON Branch (branch_name);
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```
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7. Display index Information
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```sql
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SHOW INDEX FROM Customer;
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SHOW INDEX FROM Branch;
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```
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8. Truncate table Customer
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```sql
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DROP TABLE Depositor;
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DROP TABLE Borrower;
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TRUNCATE TABLE Customer;
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```
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### Part 2:
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#### Create tables
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```sql
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CREATE TABLE Companies(comp_id varchar(50), name varchar(50), cost int, year int);
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CREATE TABLE Orders(comp_id varchar(50), domain varchar(50), quantity int);
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```
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#### Insert values
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```sql
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INSERT INTO Companies (comp_id, name, cost, year) VALUES
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("C001", "ONGC", 2000, 2010),
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("C002", "HPCL", 2500, 2012),
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("C005", "IOCL", 1000, 2014),
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("C006", "BHEL", 3000, 2015);
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INSERT INTO Orders (comp_id, domain, quantity) VALUES
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("C001", "Oil", 109),
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("C002", "Gas", 121),
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("C005", "Telecom", 115);
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```
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#### Queries
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1. Find names, costs, domains and quantities for companies using inner join.
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```sql
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SELECT name, cost, domain, quantity FROM Companies INNER JOIN Orders on Companies.comp_id = Orders.comp_id;
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```
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2. Find names, costs, domains and quantities for companies using left outer join.
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```sql
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SELECT name, cost, domain, quantity FROM Companies lEFT OUTER JOIN Orders ON Companies.comp_id = Orders.comp_id;
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```
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3. Find names, costs, domains and quantities for companies using right outer join.
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```sql
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SELECT name, cost, domain, quantity FROM Companies RIGHT OUTER JOIN Orders ON Companies.comp_id = Orders.comp_id;
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```
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4. Find names, costs, domains and quantities for companies using Union operator.
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```sql
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SELECT name, cost FROM Companies UNION SELECT domain, quantity FROM Orders;
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```
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5. Create View View1 by selecting both tables to show company name and quantities.
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```sql
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CREATE VIEW view1 AS SELECT name, quantity FROM Companies JOIN Orders ON Companies.comp_id = Orders.comp_id;
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```
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6. Create View2 on branch table by selecting any two columns and perform insert update delete operations.
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```sql
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CREATE VIEW view2 AS SELECT name, cost FROM Companies;
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SELECT * FROM view2;
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-- Insert operation
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INSERT INTO view2 (name, cost) VALUES ("BCCC", 3100);
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SELECT * FROM view2;
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-- Update operation
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UPDATE view2 SET cost = 3500 WHERE name = "BCCC";
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SELECT * FROM view2;
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-- Delete operation
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DELETE FROM view2 WHERE name = "BCCC";
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SELECT * FROM view2;
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```
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7. Display content of View1, View2.
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```sql
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SELECT * from view1;
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SELECT * FROM view2;
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```
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---
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