3.6 KiB
3.6 KiB
S1 - SQL Queries (in MySQL)
Problem Statement: Consider following Relation Account (Acc_no, branch_name,balance) Branch(branch_name,branch_city,assets) Customer(cust_name,cust_street,cust_city) Depositor(cust_name,acc_no) Loan(loan_no,branch_name,amount) Borrower(cust_name,loan_no) Create above tables with appropriate constraints like primary key, foreign key, not null etc.
- Find the names of all branches in loan relation.
- Find all loan numbers for loans made at ‘Wadia College’ Branch with loan amount > 12000.
- Find all customers who have a loan from bank. Find their names,loan_no and loan amount.
- List all customers in alphabetical order who have loan from ‘Wadia College’ branch.
- Display distinct cities of branch.
Creating the database
CREATE DATABASE Bank1;
USE Bank1;
Creating tables:
CREATE TABLE Account (
acc_no INT,
branch_name VARCHAR(255),
balance INT,
PRIMARY KEY (acc_no)
);
CREATE TABLE Branch (
branch_name VARCHAR(255),
branch_city VARCHAR(255),
assets INT,
PRIMARY KEY (branch_name)
);
CREATE TABLE Customer (
cust_name VARCHAR(255),
cust_street VARCHAR(255),
cust_city VARCHAR(255),
PRIMARY KEY (cust_name)
);
CREATE TABLE Depositor (
cust_name VARCHAR(255),
acc_no INT
);
CREATE TABLE Loan (
loan_no INT,
branch_name VARCHAR(255),
amount INT,
PRIMARY KEY (loan_no)
);
CREATE TABLE Borrower (
cust_name VARCHAR(255),
loan_no INT
);
Declaring foreign keys
ALTER TABLE Account ADD FOREIGN KEY (branch_name) REFERENCES Branch (branch_name);
ALTER TABLE Depositor ADD FOREIGN KEY (cust_name) REFERENCES Customer (cust_name);
ALTER TABLE Depositor ADD FOREIGN KEY (acc_no) REFERENCES Account (acc_no);
ALTER TABLE Loan ADD FOREIGN KEY (branch_name) REFERENCES Branch (branch_name);
ALTER TABLE Borrower ADD FOREIGN KEY (cust_name) REFERENCES Customer (cust_name);
ALTER TABLE Borrower ADD FOREIGN KEY (loan_no) REFERENCES Loan (loan_no);
Inserting data
INSERT INTO Branch VALUES
('Wadia College', 'Pune', 50000),
('PES', 'Pune', 65000),
('Lohegaon', 'Pune', 350000),
('Viman Nagar', 'Pune', 850000);
INSERT INTO Customer VALUES
('Kalas', 'Street 12', 'Pune'),
('Himanshu', 'Street 15', 'Pune'),
('Mehul', 'Street 29', 'Pune'),
('Macho', 'Street 59', 'Mumbai'),
('Gundeti', 'Street 40', 'Mumbai'),
('Salvi', 'Street 8', 'Pune');
INSERT INTO Account VALUES
(101, 'Lohegaon', 5500),
(102, 'PES', 4324),
(103, 'PES', 5467),
(104, 'Viman Nagar', 5433),
(105, 'Wadia College', 6462);
INSERT INTO Depositor VALUES
('Kalas', 101),
('Gundeti', 105);
INSERT INTO Loan VALUES
(201, 'Wadia College', 18000),
(202, 'PES', 8500),
(203, 'PES', 15000),
(204, 'Wadia College', 5322);
INSERT INTO Borrower VALUES
('Macho', 201),
('Mehul', 202),
('Himanshu', 203),
('Salvi', 204);
Queries
- Find the names of all branches in loan relation.
SELECT DISTINCT branch_name FROM Loan;
- Find all loan numbers for loans made at ‘Wadia College’ Branch with loan amount > 12000.
SELECT loan_no FROM Loan WHERE branch_name = 'Wadia College' AND amount > 12000;
- Find all customers who have a loan from bank. Find their names,loan_no and loan amount.
SELECT Borrower.cust_name, Borrower.loan_no, Loan.amount FROM Borrower INNER JOIN Loan ON Borrower.loan_no = Loan.loan_no;
- List all customers in alphabetical order who have loan from ‘Wadia College’ branch.
SELECT cust_name FROM Borrower INNER JOIN Loan on Borrower.loan_no = Loan.loan_no WHERE Loan.branch_name = 'Wadia College' ORDER BY cust_name;
- Display distinct cities of branch.
SELECT DISTINCT branch_city FROM Branch;