S4 - SQL Queries (in MySQL)

Problem Statement: SQL Queries: Create following tables with suitable constraints (primary key, foreign key, not null etc). Insert record and solve the following queries: Create table Cust_Master(Cust_no, Cust_name, Cust_addr) Create table Order(Order_no, Cust_no, Order_date, Qty_Ordered) Create Product (Product_no, Product_name, Order_no)

List names of customers having 'A' as second letter in their name.
Display order from Customer no C1002, C1005, C1007 and C1008
List Clients who stay in either 'Banglore or 'Manglore'
Display name of customers& the product_name they have purchase
Create view View1 consisting of Cust_name, Product_name.
Disply product_name and quantity purchase by each customer
Perform different joint operation.

Creating the database

CREATE DATABASE Store;
USE Store;

Creating tables:

CREATE TABLE Cust_Master (
  Cust_no VARCHAR(255) NOT NULL,
  Cust_name VARCHAR(255),
  Cust_addr VARCHAR(255),
  PRIMARY KEY (cust_no)
);

CREATE TABLE Orders (
  -- Cannot have 'Order' as table name since it is a keyword reserved for 'ORDER BY' cause
  Order_no INT,
  Cust_no VARCHAR(255),
  Order_date DATE,
  Qty_Ordered INT,
  PRIMARY KEY (Order_no)
);

CREATE TABLE Product (
  Product_no INT,
  Product_name VARCHAR(255),
  Order_no INT
);

Declaring foreign keys

ALTER TABLE Orders ADD FOREIGN KEY (Cust_no) REFERENCES Cust_Master (Cust_no);
ALTER TABLE Product ADD FOREIGN KEY (Order_no) REFERENCES Orders (Order_no);

Inserting data

INSERT INTO Cust_Master VALUES
('C1001', 'Kalas', 'Pune'),
('C1002', 'Macho', 'Banglore'),
('C1003', 'Gundeti', 'Chennai'),
('C1005', 'Salvi',  'Manglore'),
('C1006', 'Kshitij', 'Assam'),
('C1007', 'Himashu', 'Banglore'),
('C1008', 'Mehul', 'Mumbai');

INSERT INTO Orders VALUES
(1, 'C1001', '2024-11-09', 10),
(2, 'C1003', '2024-11-01', 5),
(3, 'C1005', '2024-11-05', 45),
(4, 'C1002', '2024-10-29', 3),
(5, 'C1007', '2024-10-15', 2),
(6, 'C1008', '2024-11-10', 7),
(7, 'C1006', '2024-11-09', 1);

INSERT INTO Product VALUES
('101', 'Political Stamps', 1),
('204', 'Fashion Accessory', 2),
('438', 'Complan', 3),
('327', 'ID Card Strap', 4),
('243', 'Face and Hair Wash', 5),
('373', 'Fat Reducer 6000', 6),
('327', 'Personality', 7);

Queries

List names of customers having 'A' as second letter in their name.

SELECT Cust_name FROM Cust_Master WHERE Cust_name LIKE "_a%";

Display order from Customer no C1002, C1005, C1007 and C1008

SELECT * FROM Orders WHERE Cust_no IN ('C1002', 'C1005', 'C1007', 'C1008');

List Clients who stay in either 'Banglore or 'Manglore'

SELECT Cust_name FROM Cust_Master WHERE Cust_addr = 'Banglore' OR Cust_addr = 'Manglore';

Display name of customers & the product_name they have purchase

SELECT Cust_Master.Cust_name, Product.Product_name FROM Product INNER JOIN Orders ON Product.Order_no = Orders.Order_no INNER JOIN Cust_Master ON Orders.Cust_no = Cust_Master.Cust_no;

Create view View1 consisting of Cust_name, Product_name.

CREATE VIEW View1 AS SELECT Cust_Master.Cust_name, Product.Product_name FROM Product INNER JOIN Orders ON Product.Order_no = Orders.Order_no INNER JOIN Cust_Master ON Orders.Cust_no = Cust_Master.Cust_no;

SELECT * FROM View1;

Disply product_name and quantity purchase by each customer

SELECT Cust_Master.Cust_name, Product.Product_name, Orders.Qty_Ordered FROM Product INNER JOIN Orders ON Product.Order_no = Orders.Order_no INNER JOIN Cust_Master ON Orders.Cust_no = Cust_Master.Cust_no;

Perform different joint operation.

INNER JOIN:

SELECT Cust_Master.Cust_name, Product.Product_name FROM Product INNER JOIN Orders ON Product.Order_no = Orders.Order_no INNER JOIN Cust_Master ON Orders.Cust_no = Cust_Master.Cust_no;

OUTER LEFT JOIN:

SELECT Cust_Master.Cust_name, Orders.Order_no, Orders.Order_date FROM Cust_Master LEFT JOIN Orders ON Cust_Master.Cust_no = Orders.Cust_no;

OUTER RIGHT JOIN:

SELECT Orders.Order_no, Orders.Order_date, Cust_Master.Cust_name FROM Orders RIGHT JOIN Cust_Master ON Orders.Cust_no = Cust_Master.Cust_no;

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